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5 June, 07:40

The length of a rectangle is 5 less than twice the width of the perimeter. If the perimeter rectangle is 146 find the dimensions of the rectangle

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  1. 5 June, 08:34
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    So the length would be 2w-5 = L, and 2w+2L=146. So if you substitute 2w-5 for L, you get 2w+2 (2w-5) = 146, or when you distribute 2w+4w-10=146. Simplify, and you get 6w-10=146, 6w=156, w=26. Now, plug that into the first equation for 2 (26) - 5=L, 52-5=L, 47=L. If you plug these numbers into 2w+2L, you'll find it equals 146.

    L=47

    W=26

    and, when you multiply them, A=1,266
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