A rectangle has a length at least four more than five times the width. if the perimeter is at least 44 units. find the least possible with

The answer is 3 and you get that by using the formula for the area of rectangle, p=2L+2W

44=2 (4+5w) + 2w

44=8+10w + 2w

44=8+12w

44-8=8+12w-8

36=12w

36/12=12w/12

3=w

If you plug 3 back into the original formula then you see that it is equal to the perimeter of 44

P=2 (4+5w) + 2w

P=2 (4+5•3) + 2 (3)

P=2 (19) + 6

P=38+6

P=44