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1 January, 06:41

Find the 10th term in the following arithmetic sequence if the constant being added is

-12:20,8,-12,-16

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Answers (2)
  1. 1 January, 07:09
    0
    10th term = - 88.

    Step-by-step explanation:

    This is an arithmetic sequence with first term = 20 and common difference - 12.

    nth term = a1 + (n - 1) d

    10th term = 20 + (10-1) * -12

    = 20 - 108

    = - 88.
  2. 1 January, 07:33
    0
    Find the 10th term in the following arithmetic sequence if the constant being added is - 12

    Step-by-step explanation:

    20 - 12 = 8

    8 - 12 = - 4

    -4 - 12 = - 16

    So the sequence will be

    20; 8; - 4; - 16

    an = 20 - 12 (n - 1)

    a10 = 20 - 12 (10 - 1) = - 88
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