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12 January, 01:38

22 John's father is 5 times older than john and John is twice as his sister Alice. In two years to time sum

of their age will be 58. What is their present age

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  1. 12 January, 03:01
    0
    Alice-4

    John-8

    Dad-40

    Step-by-step explanation:

    1) using the information we know if j is John's age and a is Alice's age and d if dad's age:

    2a=j

    d=5j=5 (2a) = 10a

    (a+2) + (d+2) + (j+2) = 58

    2) substitute the d and j for the equivalent terms using a so there is only one variable, Alice's age:

    (a+2) + (10+2) + (2a+2) = 58

    3) combine like terms and isolate the variable and you should get your answer.
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