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6 February, 06:01

Use properties of limits and algebraic methods to find the limit, if it exists. (if the limit is infinite, enter '∞' or '-∞', as appropriate. if the limit does not otherwise exist, enter dne.) lim x→5 x2 - 25 x - 5

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  1. 6 February, 07:10
    0
    -105

    Step-by-step explanation:

    We can do this by substituting x = 5 into the function:-

    = 5^2 - 25 (5) - 5

    = 25 - 125 - 5

    = - 105.
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