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1 January, 13:39

Verify (Prove whether true or false)

1/sec^2k=sin^2k*cos^2k+cos^4k

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  1. 1 January, 17:17
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    The expression is true.

    Step-by-step explanation:

    Step 1: Prove the expression. 1/sec²k = sin²k cos²k + cos^4k

    Left Hand Side = 1/sec²k = cos²k

    Right Hand Side = sin²k cos²k + cos^4k

    = cos²k (sin²k + cos²k) (Taking cos²k as common)

    = cos²k (∵sin²k + cos²k = 1)

    ⇒ Left Hand Side = Right Hand Side

    So the expression is true.
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