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19 May, 20:07

Factorise: a squared + 8a - 20

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  1. 19 May, 22:38
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    Factor out the 4 in both equations

    8a^2-20^2 = (2^2 times a^2 times 2) - (2^2 times 5)

    therefor it is also equal to

    (2a) ^2 times 2 - (2^2 times 5)

    we can force it into a difference of 2 perfect squares which is a^2-b^2 = (a-b) (a+b)

    (2a√2) ^2 - (2√5) ^2 = ((2a√2) - (2√5)) ((2a√2) + (2√5))
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