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3 June, 12:32

What is the center of a circle whose equation is x2 y2 4x - 8y 11 = 0? (-2, 4) (-4, 8) (2, - 4) (4, - 8)

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  1. 3 June, 14:02
    0
    Hello,

    Have you lost your "+"?

    x²+y²+4x-8y+11=0

    ==>x²+2*2x+4+y²-2*4y+16+11-4-16=0

    ==> (x+2) ² + (y-4) ²=9

    Center (-2,4) radius 3

    Answer A
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