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18 September, 20:57

How do you factor and solve this equation?

y^2-2y-8=7

+3
Answers (1)
  1. 18 September, 23:53
    0
    Ok so set one side equal to zero by subtractin g7

    now we have

    y^2-2y-15=0

    if we factor then set each factor to zero we can solve becasue if we have

    xy=0 then assume x and y=0 so

    y^2-2y-15

    find what 2 factors of - 15 add to - 2

    -5 and 3

    (x-5) (x+3)

    tada

    (x-5) (x+3) = 0

    x-5=0

    add 5

    x=5

    x+3=0

    subtract 3

    x=-3

    x=5 or - 3
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