Two positive integers $m$ and $n$ are chosen such that $m$ is the smallest positive integer with only two positive divisors and $n$ is the largest integer less than $100$ with exactly three positive divisors. What is $m+n$?

Question

Korbin Hunt

6 December, 21:30

+3

Answers (2)

Know the Answer?

Phoenix · Answer 1

Phoenix 6 December, 21:41

0

M=3

(3,1)

n=77

(1,11,7)

so m+n=80

Lexie Schmitt · Answer 2

Hello,

we only have 3 divisors if n is a square of a prime (1, a, a²) with a<10

==>n=49

and m=2

m+n=49+2=51