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8 May, 01:05

Use a linear approximation (or differentials) to estimate the given number:

1/4.002

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  1. 8 May, 03:18
    0
    Given that 1/4 = 0.25

    Set f (x) = 1/x

    Then f' (x) = - 1/x^2

    Thus 1/4.002 = f (4.002) ≈ f (4) + f' (4) * (4.002 - 4) = 1/4 - 1/4^2 * 0.002 = 0.25 - 0.000125 = 0.2499
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