Sam has a total of 58 dvd's and cd's. if the number of cd's is two more than three times the number of dvd's how many cd's does he have

a. 42

b. 14

c. 44

d. 12

We will assign the variables D and C for the number of DVD's and CD's respectively.

We know that C + D = 58

We also know that the number of CD's is two more than three times the number of DVD's written C = 3D + 2

Now we will take the entire equation of C = 3D + 2 and substitute it for C in the equation C + D = 58.

C + D = 58

(3D + 2) + D = 58

Now solve for D.

3D + 2 + D = 58

4D + 2 = 58

4D = 56

D = 14

There are 14 DVD's total. But that doesn't answer our question.

Plug in D for 14 in the equation C + D = 58 and solve for C.

C + 14 = 58

C = 44

There are 44 CD's total. So choice C. is your answer.