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1 March, 04:15

How can f (x) = 6x^2+5x-6 be factored to reveal the zeros of the function it defines

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  1. 1 March, 08:12
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    6 x^2+5 x-6

    Factor the quadratic 6 x^2+5 x-6. The coefficient of x^2 is 6 and the constant term is - 6. The product of 6 and - 6 is - 36. The factors of - 36 which sum to 5 are - 4 and 9. So 6 x^2+5 x-6 = 6 x^2+9 x-4 x-6 = 3 (3 x-2) + 2 x (3 x-2):

    3 (3 x-2) + 2 x (3 x-2)

    Factor 3 x-2 from 3 (3 x-2) + 2 x (3 x-2):

    Answer: |

    | (3 x-2) (2 x+3)

    Zeros: 2/3, - 3/2
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