Which arrangement shows 27/5, 5.36, 5 3/5, and 33/6 in order from least to greatest?

A. 5.36, 27/5, 5 3/5, 33/6

B. 27/5,5.36, 33/6, 5 3/5

C. 5 3/5, 5.36, 27/5, 33/6

D. 5.36, 27/5, 33/6, 5 3/5

To figure out these types of problems, you need to divide the numbers by each other, for example:

3/4 = 3 divided by 4 = 0.75

So, in this problem, it isn't A, because if you divide the order is 5.36, 5.4, 5.6, and 5.5

B is 5.4, 5.36 ... and the rest doesn't matter because you already know that it is not in the correct order.

Then C is 5.6, 5.36 ... and then, like B, the rest does not matter because it is obvious that it is not in order from least to greatest.

So, you can assume that your answer is D, and if you check, this is the case because the order of the numbers becomes: 5.36, 5.4, 5.5, and 5.6, which is in order from least to greatest.

Therefore, your answer is D.

The easy way to find the answer is to convert them all to decimals so 27/5 = 5.4, 5 3/5 = 5.6 and 33/6 = 5.5

so the answer is D. 5.36, 27/5, 33/6, 5 3/5