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23 September, 05:58

Given that f (x) = 3x + 1 and g (x) = the quantity of 4x plus 2

divided by 3, solve for g (f (0)).

2

6

8

9

+4
Answers (1)
  1. 23 September, 07:55
    0
    Replace x in g (x) by 3x+1 and you get:

    (4 (3x+1) + 2) / 3 = (12x+4+2) / 3 replace now x by 0 and solve

    (12*0+6) / 3 = 6/3 = 2

    So the answer is 2
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