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6 February, 20:31

Given that the rate constant for the decomposition of hypothetical compound X from part A is 1.60 M-1⋅min-1, calculate the concentration of X after 13.0min.

(min) [X] (M)

0 0.467

1 0.267

2 0.187

3 0.144

4 0.117

5 0.099

6 0.085

7 0.075

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Answers (1)
  1. 6 February, 21:24
    0
    Using the 2nd order integrated rate law.

    1/A1 = 1/A0 + Kt

    A1 = 0.267

    A0 = 0.467

    k = 1.6

    t = time

    1/A13 = 1/0.467 + 1.6 (13)

    1/A13 = 1/0.467 + 20.8

    1/A13 = 2.141 + 20.8

    1/A13 = 22.941

    1 = 22.941 * A13

    1/22.941 = A13

    A13 = 0.04359

    The concentration of X after 13 minutes is 0.04359
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