Write x^2 - 6x + 7 = 0 in the form (x - a) ^2 = b, where a and b are integers.

Question

Mathematics

Davis Hodge

2 April, 13:42

Write x^2 - 6x + 7 = 0 in the form (x - a) ^2 = b, where a and b are integers.

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Answers (2)

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Ruby Zuniga · Answer 1

X^2 - 6x + 7 = 0

x^2 - 6x = - 7

x^2 - 6x + 9 = - 7 + 9

(x - 3) ^2 = 2 < = = ur answer

Jayden · Answer 2

First, you subtract both sides with 7.

x^2 - 6x + 7-7 = 0-7

x^2 - 6x = - 7

We then do the procedure of completing the square to the left side.

x^2 - 6x + 9 = - 7+9

(x - 3) ^2 = 2

Therefore, a is equal to - 3 and b is 2.