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10 April, 07:04

How do I completely factor 4x^2-64?

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Answers (2)
  1. 10 April, 08:10
    0
    This is how you will completely factor your equation: 4 (x^2-16)
  2. 10 April, 08:30
    0
    4x^2 - 64

    = 4 (x + 4) (x - 4)
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