1. Find all solutions for the equation 4x3 12x2 - 40x = 0. Show and explain your work

To answer this question, we have to do the following:

Because I don't know if there is a + between 4x3 and 12x2 or a -, I will calculate it for both:

4x^3 + 12x^2 - 40x = 0

4x * (x^2 + 3x - 10) = 0

4x * (x+5) * (x-2) = 0

1. x = 0 (the answer for the first x in the equation)

2. x = - 5 (the answer for the second x in the equation)

3. x = 2 (the answer for the third x in the equation)

OR

4x^3 - 12x^2 - 40x = 0

4x * (x^2 - 3x - 10) = 0

4x * (x - 5) * (x + 2) = 10

1. x = 0

2. x = 5

3. x = - 2