Solve by using a matrix.

A collection of nickels, dimes and quarters totals $6.00. If there are 52 coins altogether and twice as many dimes as nickels, how many of each kind of coin are there?

a.

q = 5

d = 60

n = 30

c.

q = 15

d = 28

n = 6

b.

q = 35

d = 10

n = 5

d.

q = 10

d = 28

n = 14

Question

Carlos Bowen

30 April, 06:29

+5

Answers (1)

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Mackenzie Richard · Answer 1

Mackenzie Richard 30 April, 09:13

0

The answer is d. q=10 d=28 n=14

Solve by using a matrix.A collection of nickels, dimes and quarters totals $6.00. If there are 52 coins altogether and twice as many dimes as nickels, how many of each kind of coin are there?a.q = 5d = 60n = 30c.q = 15d = 28n = 6b.q = 35d = 10n = 5d.q = 10d = 28n = 14