Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight ... A) 29 and 31. B) 39 and 41. C) 49 and 51

X = 1st number

x + 2 = 2nd number

3/7x + 1/3 (x + 2) = 38

3/7x + 1/3x + 2/3 = 38

3/7x + 1/3x = 38 - 2/3

9/21x + 7/21x = 114/3 - 2/3

16/21x = 112/3

x = 112/3 * 21/16

x = 2352/48

x = 49 < = = 1st number

x + 2 = 49 + 2 = 51 < = = 2nd number

(3/7) x + (1/3) (x + 2) = 38

Multiply both sides by 21:

21 * (3/7) x + 21 * (1/3) (x + 2) = 21*38

9x + 7 (x + 2) = 798

9x + 7x + 14 = 798

16x = 784

x = 49

x + 2 = 51 so the are 49 and 51