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8 December, 11:16

solve the trigonometric equation

3-3cosx=2 sin^2 x

+3
Answers (1)
  1. 8 December, 14:47
    0
    = 3 - 3cos x - 2 (1 - cos^2 x)

    = 2cos^2 x - 3cos x + 1

    = (cos x - 1) (cosx - 1/2)

    now cos x = 1 or cos x = 1/2

    draw a graph we get = + ve values

    hence ... 0,180,360 and 60,240, degrees in range x<2pi
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