Ask Question
14 September, 10:35

To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 20° , and then walks off the distance to each house, 90 feet and 100 feet, respectively. How far apart are the houses?

+2
Answers (1)
  1. 14 September, 12:56
    0
    You can use trig combinations or (what i'd do) use pythagorus

    AB = sqrt[ (100^2) + (90^2) ] = 134.5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 20° , and then walks ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers