Which equation represents the general form a circle with a center at (-2, - 3) and a diameter of 8 units?

x2 + y2 + 4x + 6y - 51 = 0

x² + y² - 4x - 6y - 51 = 0

x2 + y2 + 4x + 6y - 3 = 0

x2 + y2 - 4x - 6y - 3 = 0

Equation for a circle of radius r with center at (h, k) is given by

(x - h) ^2 + (y-k) ^2 = r^2

(x - (-2)) ^2 + (y - (-3)) ^2 = 4^2

x^2 + 4x + 4 + y^2 + 6y + 9 = 16

x^2 + 4x + y^2 + 6y - 3 = 0

Rearranging, the answer is

x^2 + y^2 + 4x + 6y - 3 = 0