A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have? Which of the following equations could be used to solve the problem? x + (11 - x) = 1.70. 25x + 10 (11 - x) = 1.70. 0.10x + 0.25 (11 - x) = 1.70

X - number of dimes, y - number of quarters

x + y = 11

0.10 x + 0.25 y = 1.70

0.10 x + 0.25 (11 - x) = 1.70

We can solve it:

0.10 x + 2.75 x - 0.25 x = 1.70

0.15 x = 1.05

x = 1.05 : 0.15

x = 7 (a boy has 7 dimes and 4 quarters)

Answer: D) 0.10 x + 0.25 (11 - x) = 1.70