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20 May, 13:24

Over which interval is the graph x^2+3x+8 increasing

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  1. 20 May, 15:12
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    F (x) = x^2+3x+8

    now, the pending of the tangent line is d/dx f (x)

    f' (x) = 2x + 3

    now, we need know when the pending is increasing.

    so

    2x + 3> 0

    solving

    x>-3/2

    The interval over which the function f (x) = x^2+3x+8 is increasing is (-3/2, + ∞)
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