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14 April, 13:31

Find the volume for the regular pyramid.

slant height = 6, length of side = 4

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  1. 14 April, 16:05
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    V = 1/3 · 6 · a²√3 / 4 · h

    a = 4;

    h² = 6² - (4√3/2) ²

    h² = 36 - 11.999 = 24.001

    h = √ 24.001 = 4.8989 ≈ 4.9

    V = 1/3 · 6 · 16√3 / 4 · 4.9 = 39.2√3 = 67.9
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