A typical large orb spider has a mass of 0.50

g. if this spider suspends itself from a single 12-cm-long strand of silk, by how much will the silk stretch?

The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².

So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately:

A = πr² = (3.14) (1.5 x 10^-4 / 2) ² = 1.767 x 10^-8 m²

So this means that the amount of force we can apply before the the silk thread is broken is:

F = PA = (1.15 x 10^9) (1.767 x 10^-8) = 20.32 N

F = mg, so m = F/g = (20.32) / (9.81) = 2.07 kg!