The sum of two numbers is 58 the larger number is three more than four times the smaller number find the two numbers

X+Y=56

X=Y-16

(Y-16) + Y=56

2Y=56+16

2Y=72

Y=72/2

Y=36 ANS.

X+36=56

X=56-36

X=20 ANS. Let x = big number

Let (56 - x) = small number

The smaller number (56 - x) is 16 less than the larger number x.

This is written as (56 - x) = x - 16.

We now simply solve for x.

Once we find x, we then can find the two numbers.

56 - x = x - 16

56 + 16 = x + x

72 = 2x

72/2 = x

36 = x

The big number is 36.

The smaller number is 56 - 36 or 20.