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25 June, 05:54

N ∆ABC, if sin A = 4/5 and tan A = 4/3, then what is cos A?

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  1. 25 June, 09:20
    0
    Hello:

    tanA = sinA/cosA

    cosA = sinA / tanA

    cosA = (4/5) / (4/3)

    cosA=3/5
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