If the child pulls with a force of 19 n for 15.0 m, and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how much work does the child do on the wagon?

The solution for this problem is we will be using the formula for work which is:

Work = Fs, where F is the component of the force in the direction of motion

Horizontal component of force = F = (19 N) (cos 25) = (19) (0.906)

Fs = (190) (0.906) = 172.14 J