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14 October, 14:13

A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) How much time is required to reach this height?

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  1. 14 October, 14:36
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    Question A:17.92 m/s

    Question B:0.6 seconds

    Explanation:

    Question A:

    Initial velocity (u) = 24m/s

    Height (h) = 13m

    acceleration due to gravity (g) = 9.8m/s^2

    Final velocity=v

    v^2=u^2-2xgxh

    v^2=24^2-2x9.8x13

    v^2=24x24-2x9.8x13

    v^2=576-254.8

    v^2=321.2

    Take them square root of both sides

    v=√ (321.2)

    v=17.92m/s

    Question B:

    velocity (v) = 17.92m/s

    Acceleration due to gravity (g) = 9.8m/s^2

    Initial velocity (u) = 24m/s

    Time=t

    v=u-gxt

    17.92=24-9.8xt

    Collect like terms

    9.8t=24-17.92

    9.8t=6.08

    Divide both sides by 9.8

    9.8t/9.8=6.08/9.8

    t=0.6 approximately
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