Ask Question
3 June, 21:59

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?

+2
Answers (1)
  1. 3 June, 23:57
    0
    Use this numbers that you are given and plug them into the formule for net force

    Net force = m*a (mass times acceleration)

    Therefore the net force is equal to (5.5 kg) * (4.2 m/s^2) = 23.1 N

    Answer: Net force = 23.1 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box? ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers