A 50-kilogram student threw a 0.40-kilogram ball with a speed of 20 meters per second. What was the magnitude of the impulse that the student exerted the ball?

By definition, the magnitude of the impulse is given by

I = delta P

where,

delta P = variation of the linear amount of movement.

P = m * v

We have then:

I = delta P

I = delta m * v

I = (0.40) * (20) - (0.40) * (0)

I = 8 Kg * m / s

answer:

the magnitude of the impulse that the student exerted the ball was

I = 8 Kg * m / s