The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?

Intensity = power / Area

⇒ Power absorbed = 1 * A ⇒ 1.4 * 10∧3 * (10)

= 14000 Watt = 14 kWatt

time - averaged intensity divided by speed of light in free space is the radiation pressure

P = (1.4 * 1000) / c

Force = pressure * area ⇒ ((1.4 * 1000) / (10∧8)) * 10

= 0.00004666666N

0.000047N