What is the kinetic energy of a 72.0-kg sky diver falling at a terminal velocity of 79.0 m/s? show your work. round your answer to the thousands place and include the units with your answer?

Kinetic energy can be calculated using the formula Ke = 1/2mv^2, where m is the mass of the object in kilograms and v is the velocity of the object in m/s.

Substitution follows:

Ke=1/2mv^2

Ke=1/2 (72) ((79) ^2)

Ke=1/2 (449,352)

Ke=224,676 or 225,000

The kinetic energy of the diver is equal to 225,000 kg•m/s^2, 225,000 Joules, or 225 kilojoules (all the same value).