A pen rolls off a 0.55-meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance from the base of the table will the pen land?

To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.

Y=Yo+Voyt+1/2at^2

0=.55+0+1/2 (-9.8) t^2

-.55=-4.9t^2

sqrt (.55/4.9) = t

t=0.335 seconds

Horizontal distance

=0.335s*1.2m/s

=0.402 meters