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27 April, 18:37

A water balloon dropped from a window high above the ground falls y = 4.9t2 m in t sec. find the balloon's (a) average speed during the first 3 sec of fall. (b) speed at the instant t = 3.

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  1. 27 April, 21:39
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    For the average speed, I multiplied 4.9 by 3 squared to receive 44.1, then divided that by 3 to receive 14.7 m/s. 4.9 X 4.9 X 4.9 = 44.1 (Distance traveled / fall time) 44.1 : 3 = 14.7 m/s

    For the speed at t = 3, I took the derivative of 4.9t2 to make it 2 (4.9) t and then plugged in 3 to receive an answer of 29.4 m/s. derivative = 2 (4.9) t = 2 (4.9) 3 = 29.4 m/s
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