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18 June, 14:18

A stone is dropped from a bridge and hits the pavement below in 2 seconds. what is the velocity of the stone when it hits the pavement

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  1. 18 June, 14:52
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    Velocity of the stone just before it hits the pavement can be found by using kinematic equation v = u + at.

    u = initial velocity = 0 m/s. a = 9.8 m/s^2. t = 2 sec.

    Plug given values to find v.
  2. 18 June, 15:58
    0
    Well gravity is 9.8m/s so i would assume 19.6m/2 is the velocity
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