A ball is thrown straight up at an initial speed of 9.8m/s and, on returning to your hand, hits it moving downward at the same speed. If the whole trip took 2.0s, determine the ball's (a) average acceleration and (b) average velocity.

Question

Physics

Kaylee Garcia

12 November, 08:43

A ball is thrown straight up at an initial speed of 9.8m/s and, on returning to your hand, hits it moving downward at the same speed. If the whole trip took 2.0s, determine the ball's (a) average acceleration and (b) average velocity.

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Answers (1)

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Julianne Hansen · Answer 1

-9.8 m/s²

0 m/s

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-9.8 m/s - 9.8 m/s) / 2.0 s

a = - 9.8 m/s²

Average velocity is the change in position over change in time.

v = Δx / Δt

v = (0 m - 0 m) / 2.0 s

v = 0 m/s