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21 August, 22:16

A water-balloon launcher with mass 4 kg fires a 0.5 kg balloon with a velocity of 3 m/s to the east. what is the recoil velocity of the launcher?

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  1. 21 August, 23:57
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    I think we will use the law of conservation of linear momentum;

    M1V1 = M2V2

    M1 = 4 kg (mass of the water balloon launcher)

    V1=?

    M2 = 0.5 kg (mass of the balloon)

    V2 = 3 m/s

    Therefore; 4 V1 = 0.5 * 3

    4V1 = 1.5

    V1 = 1.5/4

    = 0.375 m/s
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