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31 August, 09:05

3. A ball is thrown up vertically, with a velocity of 20m/s. Calculate the maximum height

reached and the time taken to reach it. Calculate also the time taken for the ball to reach

the ground again.

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Answers (1)
  1. 31 August, 11:13
    0
    u=20m/s

    v=0m/s

    g = 9.8m/s^2

    h=?

    v^2 = u^2 - 2gh

    0^2 = 20^2 - 2 * 9.8*h

    19.6h=400

    19.6h/19.6 = 400/19.6

    h=20.41m

    solving for time taken for the ball to reach the ground again T = the time to reach maximum height + time the Ball takes to fall to the ground.

    The time t to reach maximum height = The time t to fall to the ground

    T = t+t

    T=2t

    u=20m/s

    v=0m/s

    g = 9.8m/s^2

    t=?

    v = u-gt

    0=20-9.8t

    9.8t=20

    9.8t/9.8 = 20/9.8

    t = 2.04seconds

    T=2t

    T=2 (2.04)

    T=4.08 seconds is the time the ball takes to reach the ground again.
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