What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 465 K? For m, use 0.0202 kg.

Answer: 757m/s

Explanation:

Given the following:

Mole of neon gas = 1.00 mol

Temperature = 465k

Mass = 0.0202kg

Using the ideal gas equation. For calculating the average kinetic energy molecule:

0.5 (mv^2) = 3/2 nRt

Where;

M = mass, V = volume. R = gas constant (8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles

Plugging our values

0.5 (0.0202 * v^2) = 3/2 (1 * 8.31 * 465)

0.0101 v^2 = 5796.225

v^2 = 5796.225 / 0.0101

v^2 = 573883.66

v = √573883.66

v = 757.55109m/s

v = 757m/s