The force between a pair of. 005 charges is 750 N. What is the distance between them?

Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?

Answer:

17.32 m

Explanation:

From coulomb's Law,

F = kqq'/r² ... Equation 1

Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.

make r the subject of the equation above

r = √ (kqq'/F) ... Equation 2

From the question,

Given: q = q' = 0.005 C, F = 750 N

Constant: k = 9.0*10⁹ Nm²/C².

Substitute these values into equation 2

r = √ (9.0*10⁹*0.005*0.005/750)

r = √ (300)

r = 17.32 m.

Hence the distance between the pair of charges = 17.32 m