An 80-kgkg quarterback jumps straight up in the air right before throwing a 0.43-kgkg football horizontally at 15 m/sm/s. How fast will he be moving backward just after releasing the ball?

V = 0.0806 m/s

Explanation:

given data

mass quarterback = 80 kg

mass football = 0.43 kg

velocity = 15 m/s

solution

we consider here momentum conservation is in horizontal direction.

so that here no initial momentum of the quarterback

so that final momentum of the system will be 0

so we can say

M (quarterback) * V = m (football) * v (football) ... 1

put here value we get

80 * V = 0.43 * 15

V = 0.0806 m/s