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11 July, 12:27

And 84.1 kg man is standing on a frictionless ice surface when he throws a 1.80 kg book at 11.1 m/s. With what velocity does the man move across the ice

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  1. 11 July, 14:08
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    Final velocity of man is - 0.23 m/s.

    Explanation:

    Conservation of linear momentum:

    When no external force acts on a system of several interacting particles, the total linear momentum of system is conserved.

    Before the Throw; Man mass (M₁) = 84.1 kg,

    Velocity of Man (u₁) = 0 m/s

    Book Mass (M₂) = 1.80 kg

    Velocity of book (u₂) = 0 m/s

    After the throw; Man mass (M₁) = 84.1 kg

    Velocity of Man (V₁) = ?

    Book mass (M₂) = 1.80 kg

    velocity of book (V₂) = 11.1 m/s

    According to conservation of linear Momentum

    Initial Momentum = Final Momentum

    M₁u₁ + M₂u₂ = M₁v₁ + M₂v₂

    84.1 x0 + 1.80 x0 = 84.1 x v₁ + 1.80 x 11.1

    0 = 84.1 v₁ + 19.98

    v₁ = - 19.98 / 84.1

    = - 0.23 m/s

    final velocity of man is - 0.23 m/s
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