Ask Question
6 July, 06:27

A bike with tires of radius

0.330 m speeds up from rest

to 5.33 m/s in 6.27's. Through

what angle do the wheels turn

in that time?

(Unit = rad)

+2
Answers (1)
  1. 6 July, 07:04
    0
    The wheels turn 101.27 radians in that time.

    Explanation:

    First, we need to find the angular velocity of the tires. We use the following formula for this purpose:

    Δv = rω

    ω = Δv/r

    where,

    ω = Angular Velocity of Tires = ?

    Δv = change in linear velocity = 5.33 m/s - 0 m/s = 5.33 m/s

    r = radius of tire = 0.33 m

    Therefore,

    ω = (5.33 m/s) / (0.33 m)

    ω = 16.15 rad/s

    Now, the angular displacement covered by tires can be found out by using the general formula of angular velocity:

    ω = θ/t

    θ = ωt

    where,

    θ = angular displacement = ?

    t = time = 6.27 s

    Therefore,

    θ = (16.15 rad/s) (6.27 s)

    θ = 101.27 radians
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27's. Through what angle do the wheels turn in that time? (Unit = ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers