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16 August, 13:46

A flute player hears four beats per second when she compares her note to a 523 {Hz} tuning fork (the note C). She can match the frequency of the tuning fork by pulling out the "tuning joint" to lengthen her flute slightly.

What was her initial frequency?

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  1. 16 August, 14:04
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    Initial Frequency = 527Hertz

    Explanation:

    Given

    Frequency of beat = 4 Hertz

    Frequency of Fork = 523 Hertz

    Let Fb = Frequency of beat

    Ff = Frequency of Fork

    The wave length and the length of the flute are directly proportional.

    So, when the wavelength gets increased, the length of the flute is also increased.

    But it is not so for the frequency.

    When the wavelength and the length of the flute are increased, the frequency gets reduced.

    For the flute player frequency to equate the frequency of the turning fork, the frequency of the flute must be greater than the frequency of the fork.

    So, Frequency = 4 + 523 = 527 Hertz
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