Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. A particle with charge q is placed at the center of the cavity. The net charge on the inner surface of the conducting shell is

Answer: in this question, the only charge in the cavity is Q. Inside the conducting spherical shell, the electric field is zero.

While outside the shell, the electric field is given by: k (q + Q) / r²

Where;

K = is a constant which is given as, 8.99 x 10^9 N m² / C².

Q = source charge which creates the electric field

q = is the test charge which is used to measure the strength of the electric field at a given location.

r = is the radius

Explanation: Inside the conducting spherical shell, the electric field is zero since the Electric field vanishes everywhere inside the volume of a good conductor.