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21 June, 22:28

Nathan accelerates his skateboard uniformly along a straight path from rest to 12.5 m/s in 2.5 s.

a. What is Nathanâs acceleration?

b. What is Nathanâs displacement during this time interval?

c. What is Nathanâs average velocity during this time interval?

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  1. 22 June, 01:12
    0
    a) Nathan's acceleration is 5 m/s² b) Nathan's displacement during this time interval is 15.625 mc) Nathan's average velocity during this time interval is 6.25 m/s

    Explanation:

    a) We have equation of motion v = u + at

    Initial velocity, u = 0 m/s

    Final velocity, v = 12.5 m/s

    Time, t = 2.5 s

    Substituting

    v = u + at

    1.25 = 0 + a x 2.5

    a = 5 m/s²

    Nathan's acceleration is 5 m/s²

    b) We have equation of motion s = ut + 0.5 at²

    Initial velocity, u = 0 m/s

    Acceleration, a = 5 m/s²

    Time, t = 2.5 s

    Substituting

    s = ut + 0.5 at²

    s = 0 x 2.5 + 0.5 x 5 x 2.5²

    s = 15.625 m

    Nathan's displacement during this time interval is 15.625 m

    c) Displacement = 15.625 m

    Time = 2.5 s

    We have

    Displacement = Time x Average velocity

    15.625 = 2.5 x Average velocity

    Average velocity = 6.25 m/s

    Nathan's average velocity during this time interval is 6.25 m/s
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